2(x^2+1.5x+1.125)=0

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Solution for 2(x^2+1.5x+1.125)=0 equation: 



2(x^2+1.5x+1.125)=0

We multiply parentheses

2x^2+2x+2.25=0

a = 2; b = 2; c = +2.25;
Δ = b2-4ac
Δ = 22-4·2·2.25
Δ = -14
Delta is less than zero, so there is no solution for the equation

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